Simple divisions returning yes/no remainder?
cponder at nvidia.com
Mon Nov 16 14:08:46 UTC 2020
I'm using these functions to compute some rounded integer quotients
Function: /void/ *mpz_cdiv_q* /(mpz_t q, const mpz_t n, const mpz_t d)/
Function: /void/ *mpz_fdiv_q* /(mpz_t q, const mpz_t n, const mpz_t d)/
I'd also like to know, though, if the remainder is non-zero without
having to perform additional arithmetic steps.
Would it be possible for these functions to return a boolean for this?
I expect that the algorithm would have some state-information that would
be easy to test at the end of the calculation, as opposed to performing
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