# Prolem with Integer Division

arthur arthur at ilvsun3.com
Sat Feb 6 15:49:53 CET 2010

Howdy Jack:

If you change
>         gmp_printf("%lu \n", n);
to
>         gmp_printf("%Zd \n", n);

your program likely works as desired.
With input 1234, it prints:
This is an even number, so 1234 = 2 x 617

/arthur

jack THE RED wrote:
> Hi everyone!
> I'm new to GMP and I have a problem regarding the integer division.
> I did read the manual and tried a lot of the division function.
>
> But the result is always something weird:
> "so 1234 = 2 x 3218735876"
> Can someone tell me what is the problem?
>
> Code:
>
> #include <stdio.h>
> #include <gmp.h>
>
>
> int main(){
>     mpz_t n;
>     mpz_t root;
>     mpz_t remainder;
>     mpz_t s;
>
>     mpz_init (n);
>     mpz_init (root);
>     mpz_init (remainder);
>     mpz_init (s);
>
>     printf("Please enter a number to by two: \n");
>     gmp_scanf ("%Zd",&n);
>
>     gmp_printf("number inputed %Zd  \n", n);
>     mpz_sqrt(root,n);
>     gmp_printf("number root %Zd  \n", root);
>     mpz_set(s,n);
>     mpz_mod_ui(remainder,s,2);//remainder <- n%2
>     if (mpz_cmp_ui(remainder,1)){// if remainder!=1 (means that n is an even number)
>
>         gmp_printf("This is an even number, so %Zd = 2 x ", n);
>         mpz_div_ui(n, n, 2); /// Error here!
>         gmp_printf("%lu \n", n);
>         }
>
>     mpz_clear (n);
>     mpz_clear (root);
>     mpz_clear (remainder);
>     mpz_clear (s);
>     return 0;
> }