Strange gcc warning.

[ezzetabi]

Roberto Bagnara <bagnara at cs.unipr.it> wrote:
> ezzetabi wrote:
> > Here a minimalistic example:
> > /* min.c */
> > #include <gmp.h> 
> > void f(const mpz_t* t) {
> >     t = t;
> > }
> > int main() {
> >     mpz_t e[5];
> > 
> >     f(e);
> >     return 0;
> > } 
> See 6.7.3#8 of the C99 standard and
>     http://c-faq.com/ansi/constmismatch.html
> All the best,
>      Roberto 

I see, then I need to use explicitly the type hidden by mpz_t?
Like this? (pretty bad because force the caller using a strange sintax)
#include <gmp.h>
void f(__mpz_struct const* t) {
    t = t;
}
int main() {
    mpz_t e[5];
    f(&(e[0][0]));
    return 0;
}
or this? (even worse since it forces the caller using an different type)
#include <gmp.h>
void f(__mpz_struct const* t) {
    t = t;
}
int main() {
    __mpz_struct e[5];
    f(e);
    return 0;
}
And there is there a way to avoid use the forbidden identifier __mpz_struct?
do exist a typedef for it that is not an array? 

Or there is a different clean solution for using const arrays of mpz_t?
ezzetabi