mpz_remove_ui
Andrew Friedley (CNS Student Support)
saai@student.cns.uni.edu
Mon, 7 Jul 2003 19:51:44 -0500
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May I suggest the addition of a variation of mpz_remove, mpz_remove_ui?
As is apparent in the attached patch, the argument f is an unsigned int,
rather than an mpz_t. I found this useful in my trial division
algorithm where my candidate factors are unsigned integers, rather than
full blown mpz_t's.
--
Andrew Friedley
CNS Computing - Student Staff
University of Northern Iowa
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diff -Naur gmp-4.1.2/gmp-h.in gmp-4.1.2-mod/gmp-h.in
--- gmp-4.1.2/gmp-h.in 2002-12-17 16:04:46.000000000 -0600
+++ gmp-4.1.2-mod/gmp-h.in 2003-07-07 19:37:49.000000000 -0500
@@ -941,6 +941,9 @@
#define mpz_remove __gmpz_remove
__GMP_DECLSPEC unsigned long int mpz_remove __GMP_PROTO ((mpz_ptr, mpz_srcptr, mpz_srcptr));
+#define mpz_remove_ui __gmpz_remove_ui
+__GMP_DECLSPEC unsigned long int mpz_remove_ui __GMP_PROTO ((mpz_ptr, mpz_srcptr, unsigned int));
+
#define mpz_root __gmpz_root
__GMP_DECLSPEC int mpz_root __GMP_PROTO ((mpz_ptr, mpz_srcptr, unsigned long int));
diff -Naur gmp-4.1.2/mpz/remove.c gmp-4.1.2-mod/mpz/remove.c
--- gmp-4.1.2/mpz/remove.c 2002-08-30 19:32:05.000000000 -0500
+++ gmp-4.1.2-mod/mpz/remove.c 2003-07-07 19:36:57.000000000 -0500
@@ -92,3 +92,74 @@
mpz_clear (rem);
return pwr;
}
+
+unsigned long int
+mpz_remove_ui (mpz_ptr dest, mpz_srcptr src, unsigned int f)
+{
+ mpz_t fpow[40]; /* inexhaustible...until year 2020 or so */
+ mpz_t x, rem;
+ unsigned long int pwr;
+ int p;
+
+ if (f <= 0)
+ DIVIDE_BY_ZERO;
+
+ if (SIZ (src) == 0)
+ {
+ if (src != dest)
+ mpz_set (dest, src);
+ return 0;
+ }
+
+ if (f == 2)
+ {
+ unsigned long int s0;
+ s0 = mpz_scan1 (src, 0);
+ mpz_div_2exp (dest, src, s0);
+ return s0;
+ }
+
+ /* We could perhaps compute mpz_scan1(src,0)/mpz_scan1(f,0). It is an
+ upper bound of the result we're seeking. We could also shift down the
+ operands so that they become odd, to make intermediate values smaller. */
+
+ mpz_init (rem);
+ mpz_init (x);
+
+ pwr = 0;
+ mpz_init (fpow[0]);
+ mpz_set_ui (fpow[0], f);
+ mpz_set (dest, src);
+
+ /* Divide by f, f^2, ..., f^(2^k) until we get a remainder for f^(2^k). */
+ for (p = 0;; p++)
+ {
+ mpz_tdiv_qr (x, rem, dest, fpow[p]);
+ if (SIZ (rem) != 0)
+ break;
+ mpz_init (fpow[p + 1]);
+ mpz_mul (fpow[p + 1], fpow[p], fpow[p]);
+ mpz_set (dest, x);
+ }
+
+ pwr = (1 << p) - 1;
+
+ mpz_clear (fpow[p]);
+
+ /* Divide by f^(2^(k-1)), f^(2^(k-2)), ..., f for all divisors that give a
+ zero remainder. */
+ while (--p >= 0)
+ {
+ mpz_tdiv_qr (x, rem, dest, fpow[p]);
+ if (SIZ (rem) == 0)
+ {
+ pwr += 1 << p;
+ mpz_set (dest, x);
+ }
+ mpz_clear (fpow[p]);
+ }
+
+ mpz_clear (x);
+ mpz_clear (rem);
+ return pwr;
+}
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